How do I graph this equation?
y=(x-3)²
Please explain. How do I get the vertex and axis of symmetry?
2006-11-13 12:16:34 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
doesn't your book, teacher, or fellow classmates have a clue?
asking such questions here, you will get a lot of crap answers.
how will you know what's right?
2006-11-13 12:21:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
OK, let's take a look at this.
y = (some number) squared.
Obviously, y is at its smallest possible value when the number in parentheses equals zero.
Hence, y is at its minimum when (x-3) equals zero,
i.e. when x = 3
When x is 3, y is 0 squared, which equals 0.
Therefore, your axis of symmetry is x=3
And your vertex is at (3,0).
Hopefully that helps!
2006-11-13 20:25:29 · answer #2 · answered by Bramblyspam 7 · 0⤊ 0⤋
dy/dx = 2(x-3) = 2x - 6
let dy/dx = 0,
2x - 6 = 0,
x = 3 (You can get the answer by inspection actually)
therefore the vertex is at coordinate (3,0) and the axis of symmetry is x = 3.
2006-11-13 20:23:46 · answer #3 · answered by ali 6 · 0⤊ 0⤋