If this is the general equation then...?

Question

If the general equation is f(t)=at^2+bt+c how do I derive the quadratic equation of f(t)= -2.0^2+10t+0.5?

Answer 1

Don't you just love the quadratic equation?

The first thing you got to do is get the given equation into the correct form, and in order to do that you have to combine all like terms. Since there are no like terms yet you have to do some math first.

-2.0^2 = 4.0because neg * neg = pos

Now you have 2 like terms 4.0 and 0.5 combine to get 4.5. Your eqution should look like this:

f(t)=10t + 4.5 since you need at^2 + bt^2 + c just insert t^2. Now your equation will look like this:

f(t)=t^2 + 10t + 4.5

And just in case you need the quadratic equation:

t= -b + or - sqr(b^2 - 4ac) / 2a

oh yeah and a = 1

Answer 2

-4t+10