4x^2 - 16 = 0
4(x^2 - 4) = 0
x^2 - 4 = 0
(x - 2)(x + 2) = 0
ANS : x = 2 or -2
2006-11-13 12:48:02
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answer #1
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answered by Sherman81 6
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4x^2 - 16=0
Take out 4 as a common factor:
4(x^2 - 4)=0
Divide both sides of the equation by 4:
(x^2 - 4)= 0
Factorise the above expression:
(x+2)(x-2) = 0
(x+2)= 0 or (x-2)= 0 [Since anything multiplied by 0 = 0)
Therefore x=2 or x=-2
2006-11-13 12:11:40
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answer #2
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answered by limck_dcp_cls 2
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There's a formula for factoring the difference of two perfect squares:
a^2 - b^2 = (a+b) (a-b)
In this case, a = 2x , b = 4
Therefore:
4x^2 - 16 = (2x+4) (2x-4) = 0
2x+4 = 0 or 2x-4 = 0
x = -2 or x = 2
2006-11-13 12:11:03
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answer #3
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answered by Anonymous
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yeah here...
4x^2-16=0
**factor into 2 parenthesis, difference of perfect square because 4 is a perfect square (2 and 2) and 16 is too (4 and 4)**
(2x + 4) (2x - 4)
figure out what x equals by making them equal to 0
2x+4=0 2x-4=0
-4 -4 +4 +4
2x= -4 2x=4
/2 /2 (divide by 2)/2 /2
x=-2 x=2
This from my math teacher so if is wrong blame her :-)
2006-11-13 12:42:28
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answer #4
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answered by xombiecats 2
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there is a formula: in your equation...A=4, B=0, C=(-16)
you start with the equation
it is negative b plus OR minus the square root of b minus 4XaXc all divided by 2Xa
start with -0 plus the square root of (0 - (4 x 4 x -16)) divided by 2 x 4
0 - the square root of 16x16 divided by 8
so 16 divided by 8 = 2
that is the first answer
the second one
- (0) MINUS the square root of (0 - (4 x 4 x -16)) divided by 4 x 2
so it is
the negative square root of 16 x 16 divided by 8
so it is -2
the answer are 2 or -2
2006-11-13 12:13:01
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answer #5
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answered by Sean M 1
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Reduce first.
4x^2=16 then continue reducing
x^2=4
Answer:
x=2
x=-2
2006-11-13 12:09:09
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answer #6
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answered by elfoxx 1
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Sure:
To isolate the variable:
Add 16 to both sides.
Divide 4 on both sides.
Take the square root on both sides.
The square root will yield a positive and a negative value.
2006-11-13 12:07:05
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answer #7
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answered by powhound 7
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