A balloon is at an altitude of 2000ft. The angle of depression from the balloon to a large rock in the center of a pond is 22 degrees, 20minutes. How far horizontally must the balloon move to be directly over the rock?
Can anyone get me to the answer please? Thanks!
2006-11-13 11:31:07 · 3 answers · asked by mdetaos 3 in Science & Mathematics ➔ Astronomy & Space
This is a trig question. I won't answer it, but will help you set up the problem.
Draw a picture with a triangle one side that is 2000 ft high and one angle (I leave it to you to figure out which one and where the rock and baloon are) is 22.3333 degrees. You also have a right angle there someplace. Angle-side-angle theorem means the triangle is uniquely defined. You can use an inverse trig function to calculate the distance from the balloon to the rock along the surface. You can also use the "sine law" of Algebra if you are not supposed to use inverse trig functions, though you have to find the subtent of the third angle (trivial if you remember one fact about triangles).
2006-11-13 16:44:36 · answer #1 · answered by Mr. Quark 5 · 0⤊ 0⤋
ur a total geek!
2006-11-13 19:33:28 · answer #2 · answered by Anonymous · 0⤊ 0⤋
do your own homework.
2006-11-13 19:38:18 · answer #3 · answered by Anonymous · 0⤊ 0⤋