above has got it!
2006-11-13 11:31:04
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answer #1
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answered by yellowpalma 2
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There aren't very many possibilities if X and Y are whole numbers, and they must also be perfect squares, otherwise their square roots would stop one equation or the other from being correct. And in the first equation, Y = 1 and Y = 4 are the only possibilities for which âX is positive. Trying Y = 1 gives âX = 6 from the first equation, and 36 + 1 = 11 in the second equation, which is wrong. Trying Y = 4 gives âX = 3 from the first equation, and 9 + 2 = 11 in the second equation, which is right - which is just as well, because there was nothing else to try.
2006-11-14 06:10:40
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answer #2
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answered by bh8153 7
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X = 9 and Y = 4
2006-11-13 13:23:22
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answer #3
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answered by simplythevest 1
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From âX +Y=7 you have x=(7-y)^2 (I)
From X+âY=11 you get y=121-22x+x^2 (II)
Substituing x from (I) in (II)
y=121-22*(7-y)^2+(7-y)^4 or rearranging
114 +7-y-22*(7-y)^2+(7-y)^4 =0 replacing (7-y) by v you get
114+v-22*v^2+v^4=0 factoring it you get (v-3)(v^3+3v^2-13v-38)=0
the v=3, but v=3=7-y and y=4 and from (II) x=9
That´s all.
2006-11-15 13:06:40
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answer #4
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answered by ES 2
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here's an iteration method for this
type of problem-in order to get
an accurate answer,reiterate
until it converges to the number of
decimal places required
sqrtx+y = 7........(1)
x+sqrt y= 11..........(2)
from (1),y=7-sqrtx
substitute into (2)
x+sqrt{7-(sqrtx)}=11
>>>x=11-sqrt{(7-sqrtx)}
we now have the iteration
x1=a good guess
x(n+1)=11-sqrt{7-sqrtx(n)}
for n=1,2,3,..........
(take the +ve values of the sqrts)
try x1=6
x2=8.866807496
x3=8.986088249
x4=8.999420204
x5=8.999977582
x6=9 (damn near it)
substitute into (1) to get y=4
it's a waste of time trying to break down
these type of problems with algebra-the
equations are too long to deal with
there are four roots in a quartic-they don't
have to be equal or real-if one iteration
diverges,another can be tried to get the
real root(s)
other prob
(take+ve roots)
x1=8,
x(n+1)=10-sqrt{5-sqrtx(n)}
n=1,2,3...........
x2=8.526374242
x3=8.557777853
x4=8.559641705
x5=8.559752291
x6=8.559758852
x7=8.559759241
substitute into first equation for x
y=2.074293377
these numbers are near enough-the
'error' is 1 in10^7(approx)
this method will work with surds or
integers in the answer
thanks for the probs
i hope that this helps
2006-11-13 21:03:29
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answer #5
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answered by Anonymous
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X = 9
Y = 4
2006-11-13 11:28:42
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answer #6
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answered by myvtecsred 2
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x=9
y=4
2006-11-13 11:32:02
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answer #7
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answered by Mr Glenn 5
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x=9
y=4
2006-11-13 11:31:49
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answer #8
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answered by Dupinder jeet kaur k 2
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I think they've got it
2006-11-13 11:37:26
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answer #9
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answered by dawleymouse 4
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