The pull tab was a major advance in the engineering desigan of beverage containers. The tab pivots on a central bolt in the can's top. When you pull upward on one end of the tab, the other end presses downward on a portion of the can's top that has been scored. If you pull upward with a 10N force, approximately what is the magnitude of the force applied to the scored section?
2006-11-13 11:24:06 · 1 answers · asked by gods1princesschanel 1 in Science & Mathematics ➔ Physics
Its the ratio of the lengths.
Its balance of angular momentum, so the length from the hinge and the forces exerted must be equal.
10 N exerted upward at 2 cm from the fulcrum means that the downward load 2mm the other direction from the fulcrum is associated with a load of 100 N.
You may not have noticed, but there are special force concentrating deformations in the surface near where the tab presses. That makes it fail at about 1/2 to 1/3 the load it would otherwise fail at.
2006-11-17 11:30:52 · answer #1 · answered by Curly 6 · 0⤊ 0⤋