8(k+3)=12k-4
-3(5-9v)=25+7v
2006-11-13 11:20:19 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
8(k+3)=12k-4
First distribute the 8!
8k+24=12k-4
Then get each like terms on either side!
So subtract 8k from both sides and add four to both sides.
This will equal: 28=4k
Now divide both sides by four.
28/4=4k/4
So 7=k
The next problem do the same thing!
Distribute the -3
So...
-15+27v=25+7v
Again, get both like terms on same side!
20v=40
divide by 20
v=2
NOW go back and check your answers!
put in 7 for k for the first problem and 20 for the second problem.
8(k+3)=12k-4
8(7+3)=12*7-4
8(10)=84-4
80=80
CHECK!
That is correct.
Now do the same to the second problem.
2006-11-13 11:21:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
8(k+3)=12k-4
8k + 24 = 12k -4
28 = 4k
7 = k
-3(5-9v)=25+7v
-15 + 27v = 25 + 7v
20v = 10
v = 1/2
2006-11-13 11:21:27 · answer #2 · answered by ʎɓʎzʎs 3 · 0⤊ 0⤋
wow... that's a hard one...
I hope someone can help you...
I tried, but I can't figure it out! Good luck!
2006-11-13 11:23:18 · answer #3 · answered by Hemp 2 · 0⤊ 1⤋
thats a very good question
2006-11-13 11:21:13 · answer #4 · answered by Anonymous · 1⤊ 0⤋
already answered
see you original question
2006-11-13 11:21:38 · answer #5 · answered by tom4bucs 7 · 0⤊ 0⤋