area of triangle help!!!!?

Question

if you have a triangle that has an area of 40ft squared, and the base is 2ft more than the height, what is the height and the base of the triangle? plz if you know the answer post it with the work and formulas you used. BUT IF YOU DON'T KNOW THE ANSWER, JUST SAY SORRY I DON'T KNOW OR DON'T ANSWER!

Answer 1

The area of a triangle is given by the formula:
A = 1/2 b * h

Let b = h + 2
A = 40

So:
40 = 1/2 (h + 2)h
40 = (h² + 2h)/2
80 = h² + 2h
h² + 2h - 80 = 0
(h + 10)(h - 8) = 0

h + 10 = 0
or
h - 8 = 0

h = -10
or
h = 8

But negative numbers don't make sense for lengths, so there is one answer:

The height = 8 ft
The base = 10 ft

Answer 2

let's say that the base is "2 + x" and the height is "x"
if you know the area to be 40 ft squared and you know the formula for finding the area of a triangle [(base x height)/2]
then you can find the lengths of the height and base
WORK
[(2 + x)(x)]/2 = 40
distribute the x and multiply both sides by 2
2x + x^2 = 80
rearrange the variables and subtract both sides by 80
x^2 + 2x - 80 = 0
use the quadratic formula
(a = 2, b = 2, c = -80)
x = 8
since -10 is negative and you cannot have a negative length, you only have one x value
since the height is 8 , just add 2 to this answer to find the base
thus, the base is 10 ft and the height is 8 ft

ANSWER
base = 10 feet
height = 8 feet

Answer 3

The formula for area of a triangle is:
base x perpendicular height /2 = 40 ft squared
therefore base x perpendicular height =80 ft squared
10 x 8 = 80
therefore base = 10 foot
height = 8 foot
Hope this helps, 10 pts please

Answer 4

Well we all know that A=bh/2, so 40=bh/2 and bh=80. Now since the base is two more than the height we can narrow it down to two numbers whose difference is 2 and product is 80.

After a little while, the numbers 8 and 10 pop up and they are your answer. The base is 10 and the height is 8.

Answer 5

area = 0.5x base x height
you know area = 40
base = 2 + height

therefore
40 = 0.5 x (2+ height) x height
40 =1height + 0.5 height^2
0= 0.5 height^2 +1height -40
0= height^2 +2height -80
now factors = (height -8) (height+10)
therefore height = 8 or -10
but measurement can't be negative
therefore height is 8
and base = 2 + 8 =10

Answer 6

Assuming you mean a right triangle
where area = bh / 2
h = height
b = base = b = h + 2

(h)(h + 2) / 2 = 40
h^2 + 2h = 80
h^2 + 2h - 80 = 0 then factor
(h - 8)(h + 10) = 0
Since length h cannot be - 10 (negative)
h must be = 8 ft.

check your work
h = 8 so b = 10
and bh / 2 = 80 / 2 = 40 sq. ft

Answer 7

A=1/2bh
40=1/2(x+2)x
80=x^2+2x
x^2+2x-80
(x-8)(x+10)
x= 8 (10 is a negative number, and distance can not be negative)
base=10
height=8

Answer 8

it fairly is valid for all triangles, the really difficulty is to discover the height even as the triangles are literally not a suitable angled triangle, because the height is the longer line commencing on the bottom with a ninety degree perspective with appreciate to the bottom and arriving on the great perspective of the triangle. now and again isn't user-friendly to discover the degree of that line.

Answer 9

u need to do a=1/2bh