2006-11-13 10:08:59 · 6 answers · asked by jennifer_jackson14 1 in Science & Mathematics ➔ Mathematics
use pythagorean theorem.
a^2 + b^2 = c^2
pluggin in
a^2 + 4^2 = 11^2
a^2 + 16 = 121
Solve for a
a^2 = 105
a = sqrt(105)
a = 10.247
2006-11-13 10:10:48 · answer #1 · answered by polloloco.rb67 4 · 1⤊ 0⤋
a^2 + b^2 = c^2
a^2 + 4^2 = 11^2
a^2 + 16 = 121
a^2 = 108
a = sqrt(108)
a = sqrt(36 * 3)
a = 6sqrt(3)
ANS : 10.392
2006-11-13 11:04:37 · answer #2 · answered by Sherman81 6 · 1⤊ 0⤋
a^2+4^2=11^2
a^2+16=121
a^2=105
âa^2=â105
a=10.247
Check:
10.247^2+4^2=11^2
121=121
2006-11-13 10:15:08 · answer #3 · answered by Anonymous · 0⤊ 0⤋
10.247......do your own homework...
a (squared) + b(squared) = c (squared)
a (squared) + 4(squared) = 11(squared)
a (squared) + 16 = 121
a (squared) = 105
(square root of )105 = a...
a= 10.24695077
3 decimal places = 10.247
2006-11-13 10:20:53 · answer #4 · answered by ladylibra 1 · 1⤊ 0⤋
c^2=b^2+a^2
11^2=4^2+a^2
121=16+a^2
121-16=a^2
a^2=105
a=10.2469507....
a=10.247
2006-11-13 10:13:38 · answer #5 · answered by Jess :) 2 · 1⤊ 0⤋
= 10.247 or
10.25 or
10.2 or
10
got any more email me i way past these these are easy
2006-11-13 10:20:02 · answer #6 · answered by Anonymous · 1⤊ 0⤋