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3x-5(3x-7)=2 (x+9) +45

2006-11-13 09:49:09 · 6 answers · asked by Anonymous in Education & Reference Homework Help

6 answers

2(x-3)-3(x+5)=3(x-2)-7
=>2x-6-3x-15=3x-6-7
=>2x-3x-3x=-6-7+6+15
=>-4x=8
=>x=8/-4=-2 ans.
3x-5(3x-7)=2(x+9)+45
=>3x-15x+35=2x+18+45
=>3x-15x-2x=18+45-35
=>-14x=28
=>x=28/-14=-2 ans

2006-11-13 10:16:04 · answer #1 · answered by alpha 7 · 0 0

I guess you want to know how to sove these equations for x, well, this is how you solve them:

2(x-3)-3(x+5) = 3(x-2)-7

first you multiply the terms inside the parenthesis per the terms outside the parenthesis.

2x - 6 - 3x - 15 = 3x - 6 - 7

now you put in one side all the terms that have an x and on the other side all the terms that don't. Remember to change symbol when you are moving from one side to the other.

2x - 3x - 3x = 6 + 15 - 6 - 7

now you operate

-4x = 8

then you divide both sides between 4 and you get

x = -8/4 = -2

ok, that's how you do the first one, the second one you do it the same ;o)

2006-11-13 18:00:07 · answer #2 · answered by mensajeroscuro 4 · 0 0

I am assuming these are two different questions.........

Question 1:
You need to start off by distributing

2x - 6 - 3x - 15 = 3x -6 -7

Collect like terms on each side

-x - 21 = 3x - 13

Move all terms containing x to one side

-8 = 4x

Divide both sides by 4

x = -2


Question 2

3x - 15x +35 = 2x + 18 + 45

-12x + 35 = 2x + 63

-14x = 28

x = -2

2006-11-13 17:57:39 · answer #3 · answered by MB 2 · 0 0

2(x-3)-3(x+5)=3(x-2)-7
2x-6-3x-15=3x-6-7
-x-21=3x-1
-4x=20
x=-5

3x-5(3x-7)=2(x+9)+45
3x-15x+35=2x+18+45
-12x+35=2x+63
-14x=28
x=-2

I forget all the terms for what I did up there, but that's the way it's done.

2006-11-13 17:57:40 · answer #4 · answered by Kballs 3 · 0 0

2x -6 -3x -15 = 3x -6 -7

x=-2

2006-11-13 17:54:07 · answer #5 · answered by Anonymous · 0 0

2x-6-3x-5=3x-6-7
-x-11=3x-13
-11=4x-13
2=4x
1/2=x
x=1/2

3x-15x+35=2x+18+45
-12x+35=2x+63
35=14x+63
28=14x
2=x
x=2

2006-11-13 18:00:20 · answer #6 · answered by Anon. 1 · 0 0

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