does any one understand this?

Question

im doing special triangles im pre alg and i dont understand it herse a problem. if a is 1/2 of cand c is 22 what is b. and this is the form a sq +b sq = c sq

Answer 1

If a is 1/2 of c, and c is 22, and a^2 + b^2 = c^2, what is b?

c = 22..... 22^2 = 484
1/2 of 22 = 11 = a...... 11^2 = 121
484 - 121 = b^2
363 = b^2
square root 363 = about 19.
What's strange about this is that b is not a whole number, and usually they make it a whole number for prealg. sure that's right above? This answer is true for your problem.

Answer 2

a = 1/2 of 22 = 11
b = ?
c = 22

Then plug it in to the formula. (a^2 + b^2 = c^2)

11^2 + b^2 = 22^2

121 + b^2 = 484

Then subtract 121 on both sides.

b^2 = 363

Then, take the square root of 363.

b = 19.1

There ya go! If you need more help, feel free to email me.

Answer 3

half of c = 22 in other words 0.5c=22
divide both sides by 0.5 to get 1 c
c=44

Plug 44 for c into the equation and solve for b
sq + bsq=44sq

Get the "number" with b by itself on one side of the =. In other words subtract sq from both sides of =.
bsq = 43sq

divide both sides of = by sq to get 1b
b=43

Answer 4

Look up the meaning for Pythagorean theorem and you will get your answer.