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The acceleration of gravity on the moon is 0.166 times that on earth, and the moon's radius is 0.273 RE. What is the escape speed for a rocket leaving the moon in units of km/s?

2006-11-13 09:14:36 · 1 answers · asked by Dee 4 in Science & Mathematics Physics

1 answers

The escape speed (Ve) can be expressed as

Ve = sqrt(2*g*r)

where g is the gravitational acceleration and r is the radius of the planet/moon. Check out the link below for information about escape velocity.

2006-11-14 04:37:54 · answer #1 · answered by stever 3 · 0 0

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