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I believe it is a. Any suggestions?
A ball is thrown up into the air. Ignore air resistance. When it is rising and reaches half of its maximum height, the net force acting on it is:

a. Equal to its weight.
b. Greater than its weight.
c. Less than its weight, but not zero N.
d. Zero N.

2006-11-13 09:09:52 · 6 answers · asked by shaft0208 1 in Science & Mathematics Physics

6 answers

Yeah, it's (a). The force acting on it is its weight (mg). The reason it's still going upward is because of its initial velocity. As it rises, it continues to slow down -- negative acceleration due to gravity.

2006-11-13 09:14:05 · answer #1 · answered by daylightpirate 3 · 0 0

C. less than its weight

If it was equal to its weight then it would be balanced and would be at maximum height ready to fall down.

2006-11-13 17:11:52 · answer #2 · answered by Anonymous · 0 0

You are correct a is right. I had a quiz on this question last semester and this was the right answer.

2006-11-13 19:26:31 · answer #3 · answered by SMS 1 · 0 0

Correct, but also true from the moment it is released, not just at the top of its trajectory.

2006-11-13 17:12:43 · answer #4 · answered by Steve 7 · 0 0

Hey this looks fimilar like my homeschool work. cool haha.

2006-11-13 18:11:07 · answer #5 · answered by Lizzie 5 · 0 0

c. not neglecting buoyancy. mg - vx(pho)xg

2006-11-13 17:17:38 · answer #6 · answered by Let'slearntothink 7 · 0 0

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