1. The polynomial f(x) divided x-3 results in a quotient of x^2+3x-5 with a remainder of 2. Find f(3). and 2. Let f(x)=x^3-8x^2+17x-9. Use the factor theorem to find other solutions to f(x)-f(1)=0, besides x=1.
2006-11-13 08:22:36 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1). f(x) = (x-3)(x²+3x-5) +2. Multiply out to get your answer.
2). f(1) =1, so we have to solve
x³-8x²+17x-10 = 0.
We know x = 1 is a root of this equation, so x-1 is a
factor of the left-hand side. The other factor, obtained
by long division or synthetic division is
x²-7x+10.
Now set this equal to 0 and solve:
(x-5)(x-2) = 0,
so the other 2 solutions are x = 5 and x = 2.
2006-11-13 08:55:03 · answer #1 · answered by steiner1745 7 · 0⤊ 0⤋
1. This means f(x) = (x-3)*(x^2+3x-5) + 2. You should be able to take it from here...
2006-11-13 16:28:46 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Wow. I took Algebra last year, and that is more like Algebra 2. My advice? See your teacher as soon as you can (BEFORE you go to class), and ask him/her, because that is a really hard question.
2006-11-13 16:31:26 · answer #3 · answered by Anonymous · 0⤊ 0⤋
YOU SHOULD MAKE YOUR ANSWER MORE CLEAR!!!!!!!!!!!!!!!
I DONT UNDERSTAND IT
2006-11-13 16:28:23 · answer #4 · answered by S_Q_R 1 · 0⤊ 1⤋