I'm trying to figur out these problems:
The team won 22 games and lost 10 games. What was the percentage of wins?
and:
The record was 26 wins and 8 losses. What was the percentage of wins?
2006-11-13 08:05:55 · 8 answers · asked by Anonymous in Education & Reference ➔ Homework Help
If you need to work this out the long way in order to understand it, the best thing to do would be to cross multiply. A percentage is always out of 100...so, figure out the total number of games first:
22+10=32, So, they have won 22/32 games--now is where you cross multiply to figure that out as a percentage:
22/32=?/100
To find out the ? you multiply the top number from one set (in this case, the 22 from 22/32) by the bottom number in the other set (?/100) and then divide it by the remaining number.
So, (22*100) / 32
= 2200/32
=68.75
Do the same for the second question:
26 + 8 = 34
26/34 = ?/100
(26*100) /34
=2600 / 34
=76.47
I know that's a lot more information than the people who have just given you the answer, but I want to help you understand how to do it yourself so that you know what you're doing on a test.
I hope you understand how I worked it out.
2006-11-13 08:17:06 · answer #1 · answered by Anonymous · 0⤊ 0⤋
22 wins + 10 losses = 32 total games.
so they won 22 out of 32. Take 22 and divide it by 32 which = .68
Move the decimal 2 places to the right, and you have 68% wins.
same with the next one:
26 wins + 8 losses = 34 total games.
so they won 26 of 34 games. Take 26 and divide it by 34 which = .76
Move the decimal 2 to the right, and you have 76% wins.
2006-11-13 08:14:14 · answer #2 · answered by westsidesnowgirl 2 · 0⤊ 0⤋
add 22 and 10 so u get all the games played then divide 22 by 32 and u get ur percent. which is about 69%
add 26 and 8 then divide 26 by 34 and u get ur percent which is about 76%
2006-11-13 08:43:22 · answer #3 · answered by crazy baby 1 · 0⤊ 0⤋
the team won 22 and lost 10. this means that they played 32 games alltogether.
the percentage can be found using the following calculation:
(games won / all games played) x 100 =
(22/32) x 100 = 68.75%
the record is
(26/32) x 100 = 81.25%
The percentage of wins is 81.25%.
2006-11-13 08:11:45 · answer #4 · answered by Anonymous · 1⤊ 0⤋
you do the amount ur looking for over the whole so it would be 22/32 then u divide 22 bye 32 , move the decimal and there's ur answer. same with the other one.
2006-11-13 08:07:57 · answer #5 · answered by snorfgoogle 3 · 0⤊ 0⤋
hi in first case the % is (12 x 100)/22 = 54.54
in second case the % is (18 x 100)/26 = 69.23
2006-11-13 08:11:36 · answer #6 · answered by mane 5 · 0⤊ 0⤋
divide the total number of wins over the total number of games x 100. There's your answer.
2006-11-13 08:14:41 · answer #7 · answered by Anonymous · 0⤊ 0⤋
multiply
2006-11-13 08:08:35 · answer #8 · answered by bev 5 · 0⤊ 0⤋