using this formula b^2 - 4ac < 0 how do you find the zero amount?

Question

equation
3x2 - x + 6 = 0
discriminant
(-1)2 - 4(3)(6) = -71

where does the 72 come from?

Answer 1

What??

3x2 - x +6 = 0
6 -x +6 = 0
12 - x = 0
when x is 12 the equation is zero.
when x is less than 12, the equation is less than zero.



(-1)2 - 4(3)(6) = x
-2 - 72 = x
-74 = x

Answer 2

I thought that this was what you were trying to write:
The quadratic equation: 3x² − x + 6 = 0
If so,
The solution: x = [ −b ± √(b²−4ac)] ÷ (2a)
(b² − 4ac) is the discriminant.

The discriminant is (−1)² −4×3×6 = 1 − 72 = −71
If the discriminant is negative, you get a complex conjugate pair as your pair of solutions (your "zero"s).

It SHOULD be something like −1/6 ± i(√71)/6 where i ≡ √(−1), but I'm getting something wrong, so we need someone to come help out with more information.

Sorry this is incomplete.