I believe the answer is d since gravity doesn't change. But I just wanted to be sure. Thanks!
A hockey puck slides off the edge of a table with an initial velocity of 20 m/s. The height of the table above the ground is 2.0 m. What is the acceleration of the ball right after it leaves the table?
a. 20 m/s to power of (exponent).
b. 4.9 m/s to power of (exponent).
c. 19.6 m/s to power of (exponent).
d. 9.8 m/s to power of (exponent).
2006-11-13 07:58:21 · 4 answers · asked by shaft0208 1 in Science & Mathematics ➔ Physics
d is the most correct answer, yes.
However keep in mind that despite g being the "gravitational constant", acceleration caused by gravity DOES change depending on the the distance from the earth. When we're talking about the difference of a table, there is practically no difference, however keep in mind that it does change.
2006-11-15 14:46:27 · answer #1 · answered by tavla6611 2 · 0⤊ 0⤋
The forward velocity does not matter, gravity will still pull on it just the same. So, the acceleration in the question has to be gravity, which would be 9.8 meters per second, per second, or 9.8 m/s squared. Or answer "d" to the second power, an exponent of 2. It's all the same thing
2006-11-13 16:08:28 · answer #2 · answered by mrdanman@sbcglobal.net 2 · 0⤊ 0⤋
I believe "d", 9.8m/s/s is most correct. You're ignoring the negative acceleration due to air friction, right?
2006-11-13 16:04:21 · answer #3 · answered by Richard S 6 · 0⤊ 0⤋
Yes you are correct! d is the answer.
2006-11-13 19:32:41 · answer #4 · answered by SMS 1 · 0⤊ 0⤋