what numbers can b be
2006-11-13 07:44:57 · 3 answers · asked by unkown dub 1 in Science & Mathematics ➔ Mathematics
b^2 + 6b -16 = 0
(b+8)(b-2)=0
b+8=0
b=-8
b-2=0
b=2
2006-11-13 07:49:13 · answer #1 · answered by yupchagee 7 · 16⤊ 0⤋
General help on factoring:
Look for two numbers that when multiplied equal -16 and when added equal +6
how about -2 and +8 ?
That's how it's done!
(x-2)(x+8)
This is always what to look for. It's much better than using the quadratic formula. Only use the QF if no easy integers work.
2006-11-13 15:59:43 · answer #2 · answered by modulo_function 7 · 0⤊ 0⤋
my working style is
b^2 + 6b - 16 = 0
b 8 8b
b -2 -2b
----------------------
b^2 -16 6b
(b+8)(b-2)=0
so
(b+8)=0 and (b-2)=0
b= -8 and b=2 (solved)
hope u understand =)
2006-11-13 19:35:03 · answer #3 · answered by Anonymous · 0⤊ 0⤋