2006-11-13 07:16:26 · 26 answers · asked by henry l 1 in Science & Mathematics ➔ Mathematics
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2006-11-13 07:18:16 · answer #1 · answered by Anonymous · 1⤊ 2⤋
If the number of cows sent is 1/6 of the original, then:
Fraction left = 1 - 2/3 - 1/6 = 1/6
2006-11-14 11:49:13 · answer #2 · answered by Kemmy 6 · 0⤊ 0⤋
1) one way to do this is to say 2/3 of the cows is 8 (12/3 x2) leaves 4 cows. 1/6 of the original 12 is 2. so he'd be left with 2 cows - that's 1/6 as we just said.
2) another way to do this problem is to "equalise the denominators". 2/3 is the same as 4/6. so he's getting rid of 4/6 + 1/6 of the cows = 5/6, leaving him with 1/6
2006-11-13 09:47:31 · answer #3 · answered by stinkycatwoman 1 · 0⤊ 0⤋
Do this:
12(2/3)=8 cows
12(1/6)=2 cows
12-(8+2)=2 cows or 1/6 of them left.
2006-11-13 07:26:09 · answer #4 · answered by Anonymous · 0⤊ 0⤋
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2006-11-16 15:22:52 · answer #5 · answered by frankmilano610 6 · 0⤊ 0⤋
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2006-11-14 07:06:29 · answer #6 · answered by Anonymous · 0⤊ 0⤋
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2006-11-13 13:27:48 · answer #7 · answered by simplythevest 1 · 0⤊ 0⤋
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2006-11-13 07:23:39 · answer #8 · answered by Anonymous · 1⤊ 0⤋
12 x 2/3 = 24/3 = 8 = cows sold
12 x 1/6 = 12/6 = 2 = cows sent
8+2=10 therefore 12- 10 = 2 . therefore he still has 2 cows
2006-11-13 07:21:31 · answer #9 · answered by N T 2 · 2⤊ 0⤋
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2006-11-13 07:20:57 · answer #10 · answered by Anonymous · 1⤊ 1⤋