answer (a. 0,4) (b. -5,5) (c. -4,7) (d. 0,3,-28)
2006-11-13 07:05:36 · 9 answers · asked by unkown dub 1 in Science & Mathematics ➔ Mathematics
c.(-4,7)
2006-11-13 07:09:41 · answer #1 · answered by Anonymous · 4⤊ 0⤋
the roots of y^2-28=3y
rewrite y^2-3y -28 =0
roots r1 = (3 -(9-4*28)^0.5)/2 =- 4 ; r2 = (3 +(9-4*28)^0.5)/2 = 7
2006-11-13 07:11:29 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
y(y) - 3y - 28 = 0
(y + 4) x (y - 7)
so, (c.-4,7)
2006-11-13 07:10:09 · answer #3 · answered by curious moper 6 · 0⤊ 0⤋
y^2 - 28 = 3y
Move everything to one side:
y^2 - 3y - 28 = 0
Now factor this out. You should be able to see the answer from here.
2006-11-13 07:09:21 · answer #4 · answered by talons_pryde2000 2 · 0⤊ 1⤋
y squared - 3 y - 28 = 0
(y-7)(y+4)=0
answer is (c)
2006-11-13 07:09:10 · answer #5 · answered by Alex G 3 · 0⤊ 1⤋
the answer is c
for -4
-4*-4=16
16-28=-12
-12=3*-4
for 7
7*7=49
49-28=21
21=3*7
2006-11-13 07:11:30 · answer #6 · answered by .::♥:Good-Bye:♥::. 2 · 0⤊ 0⤋
y^2-28=3y
y^2-3y-28=0
(y-7)(y+4)=0
y=7
y=-4
c, -4,7
2006-11-13 08:08:45 · answer #7 · answered by yupchagee 7 · 0⤊ 0⤋
Man,
Stay away from the magic mushrooms, LOL bUBBA
2006-11-13 07:08:37 · answer #8 · answered by fsjock 2 · 0⤊ 1⤋
c. -4,7
2006-11-13 07:20:21 · answer #9 · answered by Anonymous · 0⤊ 0⤋