The Bases of a base ball diamond are 90' apart. Find the distance from home plate to second base in feet, inches
2006-11-13 06:02:08 · 4 answers · asked by Levi M 1 in Science & Mathematics ➔ Mathematics
I believe it's 120 feet from home plate to 2nd base, so that would equal to...1,440 inches
2006-11-13 06:05:09 · answer #1 · answered by Jammin' On The One 3 · 0⤊ 2⤋
remember a^2+b^2=c^2
a baseball diamond is 2 right triangles attached, so...
90^2+90^2=the distance from homeplate to second base
the answer should be:127.27922 feet
or 127 feet 4 inches approx.
2006-11-13 14:14:03 · answer #2 · answered by MIGHTYDOE 2 · 0⤊ 2⤋
It's a right triangle so use pythagoras' theorem. a^2 + b^2 = c^2
a = 90
b = 90
8100+8100=c^2
c^2 = 16200
c = 127.28 ft
Convert .28 ft to inches...
.28ft x (12in/1ft) = 3.36 in
Answer is 127 ft 3.36 in
2006-11-13 14:15:59 · answer #3 · answered by Brian 3 · 0⤊ 1⤋
sin(45) = 90 / h
h = 90 / sin(45) = 105.769923 feet
or 105 feet
and .77 * 12 = 9.24 inches
2006-11-13 14:06:38 · answer #4 · answered by DanE 7 · 0⤊ 3⤋