a^2+2ab+b^2/a+b + a^2-b^2/a-b + a-b/a+b divided by a^2-b^2/a+b?

Question

i really don't get this question....so confusing......i need help...pls....

Answer 1

(A^2+2ab+b^2)/(a+b) + (a^2-b^2)/(a-b) + (a-b)/(a+b)/(a^2-b^2)/a+b)
(a+b)^2/(a+b)+(a+b)(a-b)/(a-b)+ (a-b)/(a+b)*(a+b)/(a^2-b^2)
a+b+a+b+(a-b)/((a+b)(a-b))
2a+2b+1/(a-b)

if I got all the ( ) in the right places.

Answer 2

Try rewriting the equation.

For example; a^2 + 2ab + b^2 can be rewritten as (a+b)*(a+b)

Or, a^2-b^2 can be rewritten as (a-b)*(a+b)

I added the multiply sign "*" for clarity.

I believe that after rewriting the equation you will find that several of the elements in the numerators and denominators will "divide" out and thus simplify the equation.

Good luck.

Answer 3

a²+2ab+b² / a+b
(a+b)(a+b)/ a+b
a+b

a²-b²/a-b
(a-b)(a+b)
a+b

a-b/a+b

[ a+b + a+b + (a-b/a+b) ] / a²-b²/a+b

[ a+b + a+b + (a-b/a+b) ] / (a-b)(a+b)/a+b

[ a+b + a+b + (a-b/a+b) ] / (a-b)

[2a+2b + a-b/a+b] * (1/a-b)

[ 2(a+b) / a-b ] + [ (a-b)(a+b)/(a-b) ]

[ 3(a+b)(a-b) ] / (a-b)

3(a+b) or 3a + 3b <-------answer