2006-11-13 04:36:57 · 8 answers · asked by blublamblu 1 in Consumer Electronics ➔ Cell Phones & Plans
My lad gets loads from O2
2006-11-13 04:50:27 · answer #1 · answered by g4vkeuk02 1 · 0⤊ 0⤋
There's lots of websites advertising this, try http://www.02.co.uk/ and you could also try using a search engine for free sim cards to see what turns up. You should get quite a few sites from this.
Failing all that, give me a shout! I have quite a few brand new unopened 02 and orange sim packs!
2006-11-13 05:02:48 · answer #2 · answered by ~ Arwen ~ 3 · 0⤊ 0⤋
sure and certain i recieved mine per week later i have been given 4 this time as u can get up to 4 at a time they are on first come first served foundation so only watch for the provide back an keep making use of i'm getting bout 4 each and each month yet gained't practice next time so supplies extra probability to get yours
2016-11-23 19:39:22 · answer #3 · answered by vanderburg 4 · 0⤊ 0⤋
Go to ask jeeves for free stuff, and there is loads of websites that give them away.
Even o2 give them away occasionally.
2006-11-13 04:41:04 · answer #4 · answered by scragette2000 5 · 0⤊ 0⤋
sorry but it is only £5 from o2 shops
2006-11-13 04:42:18 · answer #5 · answered by penningtonuk2000 3 · 0⤊ 0⤋
hotest deal online i find on net is
www.freesim.co.nr
i ordered last week (you can order up to 4 free sim cards with free text messages) and i have it now, cool
try it bro
keep r real and enjoy !!!!
2006-11-13 04:44:03 · answer #6 · answered by Anonymous · 0⤊ 0⤋
there are websites that give them away, as said before, and yes 02 do advertise them occasionally, you can see them above banners on websites sometimes. i hav 20 of them, i ordered them at different addresses next door to me and put my name on it so my neighbours though that it was a typing error on the address thing on the letter and knocked next door and gave it to me.
2006-11-13 05:36:55 · answer #7 · answered by mcguiness403@btinternet.com 2 · 0⤊ 0⤋
aol are advertising them free on the site
2006-11-13 04:40:45 · answer #8 · answered by peter s 3 · 0⤊ 0⤋