chemical compound?

Question

When Aluminum is heated with an element from group VI of the periodic talbe, Al forms an ionic compound. On the occasion, the group VI elmente was unknown but the compound was 35.93% Al by weight. Identify the unknown element

Answer 1

Al always has a charge of +3, and the elements in group VI all have a charge of -2. Thus, your chemical formula is going to be Al(2)X(3).

Since there are two atoms of Al, that comes out to about 54 daltons, so it's just math from here. .3593 = 54/n, you will find n comes to about 150, which is the total mass of the molecule. Thus the three molecules of X comes to a total mass of 150-54=96, and since there are three of them, each one weighs 96/3 = 32, which is the mass of sulfur.

Answer 2

al with a group vi element will form the compound Al2X3 where X is the element.

so the molar mass of X3 would be 54÷35.93×64.07= 96

Al= 27 so Al2 would be 54...

now X3 is 96 g/mol. so divide this by 3 and you will get the element's molar mass. 32g/mol. that's sulphur.

Answer 3

let X be that compound

the salt with aluminium has the formula Al2 X3

Al 2 = 27+2 =54

the weight of the compound is 150.9 for x3 x = 50

And you find selenium

Answer 4

Al2 = 54
S3 = 96
Al2S3 = 150
54/150 = 0.36 = 36%

However, I OBJECT to this question!!! It says:
"... Al forms an ionic compound."
The electronegativity of Al is 1.5. For S, it's 2.5. 2.5 - 1.5 = 1.0. Al2S3 is COVALENT.