Take a beaker filled with water.pressure at its surface will be equal to atmos. pressure.now insert in it a bent pipe which connects it to another beaker L meter above the first one and having its surface parralel to the first one. it will too have pressure equal to atmos. pressure.but according to formula P = Heg the pressure at upper beaker should be (atmos.P)- (Leg )
2006-11-13 02:57:58 · 3 answers · asked by archit p 1 in Science & Mathematics ➔ Physics
where is the mistake.
2006-11-13 02:58:59 · update #1
If the tube is filled with water, when the tube is inserted water will flow from the upper beaker to the lower one by siphoning.
The pressure difference will be due to the weight of the water in the upper beaker that is above the surface of the lower beaker.
2006-11-13 03:03:47 · answer #1 · answered by DanE 7 · 1⤊ 0⤋
I don't know what those symbols stand for but the higher beaker's pressure at the surface P1 will be the lower beaker's surface pressure P0 minus g * air density * L. If we're just talking surface pressures, the water and its density and the siphon action don't apply.
2006-11-13 11:13:08 · answer #2 · answered by kirchwey 7 · 0⤊ 0⤋
There's only one thing to remember when comparing the pressure at the surface of any vessel open to the atmosphere: Is there a difference in water level? If yes, then there's a difference in pressure, with the vessel having a lower water level having greater pressure than the vessel with a higher water level. If no, as in the question you have described, then there is no pressure difference, i.e, the pressure in one is the same as the pressure in the other.
2006-11-13 11:50:55 · answer #3 · answered by tul b 3 · 0⤊ 0⤋