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use the definition of the derivative to compute the derivative of f(x)= (x+1)/(x-4)

its only asking me to find the derivative of the function right?
and the answer is (-5x)/(x-4)^2 right?

i just want to know cause i got this wrong on the test

2006-11-13 02:32:32 · 4 answers · asked by infiniti1113 3 in Science & Mathematics Mathematics

4 answers

The derivative is [(x-4)- (x+1)]/(x-4)^2 = -5/(x-4)^2

If we use the definition of the derivative:


dy/dx = Lim h -> 0 {f(x+h) -f(x)}/h
= lim h-> 0 [(x+h+1)/(x+h-4) - (x+1)/(x-4)]/h
(x+h+1)(x-4)-(x+1)(x+h-4)
= lim x-> 0 ---------------------------------------
(x+h-4)(x-4)h

= lim h-> 0 -5h/(x+h-4)(x-4)h = -5/(x-4)^2

2006-11-13 03:13:54 · answer #1 · answered by ironduke8159 7 · 0 0

i'm getting just -5/(x-4)^2
is that what you meant?
if so, mabye you didn't use the definition of derivative (the limit usage)

2006-11-13 10:41:00 · answer #2 · answered by Europa C 1 · 0 0

the ans is 5 / ( x-4)^2

2006-11-13 10:50:55 · answer #3 · answered by skjw88 1 · 0 0

a=(x+1) b=(x-4)

a'b-ab'/b^2

2006-11-13 10:46:35 · answer #4 · answered by zeck 1 · 0 0

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