calculus help..me pls.....thanks?

Question

Find the slope of the tangent to the curve at the given point.
1) y=7-x^2+4x^3 ,(-1 , 2)
2)y=3x^2-4/x ,(2 , 10)

Answer 1

To do this you need to find the derivative of the function and the plug in the "x" value from your point.

The derivative of y = 7 - x^2 + 4x^3 is 2x - 12x^2
2(-1) - 12(-x)^2 = -14

The derivative of )y = 3x^2 - 4/x is 6x + 4/x^2
6(2) + 4/2^2 = 13

Answer 2

the answers are 1)14,
2)11