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if a milkman has two 40 litre can's and one 5 litre can and one 4 litre can. How can he fill 2 litre each in 5 litre and 4 litre cans?........ and he has nothing else thing to measure milk quantity...

2006-11-12 17:14:47 · 6 answers · asked by parwan005 1 in Science & Mathematics Mathematics

6 answers

Too easy as written- he can do it with ONLY ONE 40 litre can!
Fill the 5
dump into the 4, so theres 1 left in the 5
dump the 1 from the 5 into the 40
discard the milk in the 4 and repeat the process, dumping the 1 into the 40.
now theres 2 in the 40.
discard the milk in the 4
fill the 5
dump into the 4, so theres 1 left in the 5.
discard the milk in the 4 & dump the 1 from the 5 into the 4
fill the 5 and dump into the 4, so theres 2 left in the 5.
discard the milk in the 4 and dump the 2 from the 40 into the 4.

2006-11-12 17:19:19 · answer #1 · answered by Scott R 6 · 1 2

Pour milk into one 5 litre. Pour the milk from the 5 litre into the 4 litre. This will leave 1 litre in the 5 litre can. Pour this into one 40 litre can, and repeat the whole process to get 2 litres in one 40 litre can. Do this two more times with the other 40 litre can, to get 2 40 litre cans with 2 litres milk each. Pour the milk from one 40 litre into one 5 litre, and the mile from the other 40 litre into the 4 litre.

2006-11-13 01:19:32 · answer #2 · answered by Anonymous · 0 2

Put 30 gallons into each 40 liter can by filling and dumping the the 5 gallon can, six times (for each 40 liter).
Then fill the 4 gallon can and empty it into each four liter can, 2 times each. Each 40 liter can now has 38 gallons.
Fill the 4 liter can and empty it into the 5 liter can. Then, use the 5 liter can (containing 4 gallons) to fill one of the 40 liter cans. The 5 liter can now contains 2 gallons.
Fill the 4 liter can and use it to fill the othe 40 liter can. The 4 liter can now has 2 gallons.

2006-11-13 01:29:02 · answer #3 · answered by limendoz 5 · 0 2

I am just trying, but I hope this gonna work out :D
he pours the milk from the 40 liters can to the 5 liter can, and then pour it back to the 2nd 40 liter can, and keep doing that for 6 times total, it mean he pours 30 liters already, and he pours it to the 4 liter can, and pour it back the 2nd 40 liter can, and do it one more time, so he have 2 liters left in his 40 liter can, all he can do now is pour it to 5 liter can ^^.
he has 38 liters left, he pours it to his 4 liter cans for 9 times, and he pours 36 liters, he has left 2 liter, pour it in the 4 liters can again, here you go, you have 2 liters in 5 liter can , and another 2 liters in 4 liter can.
USE SOME MATH CALCULATION

2006-11-13 01:27:17 · answer #4 · answered by Anonymous · 0 3

fill 4
dump 4L into 5L
fill 4 again
dump 1L from 4 into 5 since there's only 1L of space left in 5
dump out 5 L
dump the remaining 3L in 4 to 5
fill 4
dump 2 L to fill up 5 and u have 2 L in 4
take that 2 L and put it into one of the 40L cans
repeat process

2006-11-13 01:18:22 · answer #5 · answered by Moo 4 · 0 2

I use the foolowing notation : Q 40 liter can, W 5 liter can, E 4 liter can. QR means fill W from Q. .
So here comes the solution
QW,WE,WQ,QW,WE. now we have 2 liters in E
ther rest goes similar.

2006-11-13 01:25:11 · answer #6 · answered by gjmb1960 7 · 0 3

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