How much of an 80% nitric acid solution must be added to a 175 g of a solution that is 12% nitric acid to produce a 60% nitric acid solution??
work too please. thank you very much. appreciate it. :]
2006-11-12 16:49:44 · 3 answers · asked by bluenecklace 2 in Science & Mathematics ➔ Mathematics
The way to do this problem is to consider how much of the solution is water and how much is pure nitric acid.
175 g * 0.12 = 21 g of pure nitric acid
175 g * 0.88 = 154 g pure water
Now we add x grams of an 80% solution
0.80 x is the amount of pure nitric acid being added
0.20 x is the amount of pure water being added
21 + 0.80x
-------------- = 0.60
175 + x
105 + 0.6 x = 21 + 0.8 x
84 = 0.2 x
x = 420 g
2006-11-12 17:00:03 · answer #1 · answered by z_o_r_r_o 6 · 0⤊ 0⤋
Go with zorro, checks out
2006-11-13 01:07:31 · answer #2 · answered by Todd 1 · 0⤊ 0⤋
do your own homework!!!! LOL :)
2006-11-13 00:51:38 · answer #3 · answered by Anonymous · 0⤊ 0⤋