I get 1.69522 g/L, using constants with the most significant figures I can find:
N/V = P/(R*T)
P = 101.325e3 Pa
V = 1 m^3
R = 8.314472
T = 273.15 K
N/m^3 = 44.6149 mol/m^3 = 0.0446149 mol/L
1 mol of F2 = 37.9968 g
0.0446149*37.9968 = 1.69522 g/L
If I use 100 KPa (1 bar) as standard pressure, I get 1.67305 g/L
The difference in the values given in the answer and the "Handbook of Chem. & Physics" is apparently due to the shift from 1 atm to 1 bar as the definition of "standard pressure."
I think the slight difference in my calculated value and the published one may be due to the fact that when you start getting out to that many decimal places even "ideal gases" aren't totally ideal....maybe I should try the Redlich-Kwong EOS...
Oooooops! I didn't want to do your homework for you...maybe I should erase all this....:)
2006-11-12 17:03:22
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answer #1
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answered by pack_rat2 3
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Fluorine Density
2016-12-14 14:30:49
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answer #2
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answered by Anonymous
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Density Of Fluorine
2016-11-02 21:13:12
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answer #3
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answered by canevazzi 4
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The Handbook of Chemistry and Physics gives the density of fluorine gas as 1.667 grams per Liter and this is usually given at STP.There was no "work" involved; I just looked it up.
2006-11-12 16:26:56
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answer #4
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answered by Mad Mac 7
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For the best answers, search on this site https://shorturl.im/mZVCl
The molar density of any ideal gas at STP is: 1 mol / 22.4 L = 0.04464 mol / L The molar mass of F2 is: 2(19) = 38 g/mol 0.04464 mol / L * (38 g / mol) = 1.70 g/L
2016-03-29 02:53:33
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answer #5
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answered by Anonymous
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At STP : pressure = 1 atm and T = 273 K Molar mass = d x RT / p = 2.176 x 0.0821 x 273 / 1 atm = 48.77 g/mol This is not enought to find the formula
2016-03-19 22:46:15
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answer #6
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answered by Anonymous
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This Site Might Help You.
RE:
What is the density of fluorine gas at STP?
a.) .848 g/L
b.) 1.55 g/L
c.) 1.70 g/L
d.) 1.85 g/L
please show work!
2015-08-19 01:14:52
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answer #7
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answered by Fidel 1
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It is 0.848 g/L
density = mass/volume
volume of 1 mol of a gas at STP is always 22.4 L so since Florine has 18.998 g
Therefore d=18.998/22.4 = 0.848 g/L
2014-12-01 15:21:40
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answer #8
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answered by Anonymous
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