let your given point be P(a,b,c...) and your slope be a direction given by a vector V(v,w,x,....). I'm assuming you want a vector equation of a line? You can get to any point on the line by starting at P and moving some distance m (maybe negative) in the direction V. So any point R(r,s,t,...) on the line is given by
R = P + mV, where m is some real number.
For example, in 2 dimensions, the line y = (2/3)x + 1 has a y-intercept at (0,1). Let that be P. The slope 2/3 is the vector (3,2). The point (2, 7/3) is on the line, and the equation
(2, 7/3) = (0,1) + m(3,2) works when m = 2/3. m/√13 is the distance you go along the line from P to R.
2006-11-12 18:40:24
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answer #1
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answered by Philo 7
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y = mx + b
You have everything but b, which is the y intercept.
(2,3); slope 2
3 = 2(2) + b
-1 = b
y = 2x -1 is the equation in slope/intercept form. I'm not sure what a vector equation is.
2006-11-13 00:21:19
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answer #2
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answered by ASUfan 1
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the point p interprete it as a vector.
then eq for the oine that goes throug p and has a given slope v
p + v(1,0) // in case of dimension 3 y will need two slopes
2006-11-13 01:36:39
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answer #3
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answered by gjmb1960 7
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