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If sin(theta)=theta, what does cos(theta)= ? too? (for small angular aproximation)

2006-11-12 16:08:17 · 4 answers · asked by Dani S 1 in Science & Mathematics Mathematics

4 answers

sin(θ) ≈ θ
So cos (θ) ≈ 1 because cos (0) = 1
More accurately cos (θ) ≈ 1 - θ²/2

2006-11-12 16:21:46 · answer #1 · answered by Wal C 6 · 0 0

The power series for sin has all odd power terms beginning with x

sin x = x + x^3/3! + x^5/5! + ....

cos has only even powers starting with x^0 = 1:
cos x = 1 + x^2/2! + ...

Thus for very small values of x you can use just the first term as the approximation...

Consider how angles in radians are defined. Compare it to angles on a unit circle. You can see clearly the validity of the approx.

This is a fairly standard way to deal with small values....

2006-11-13 00:16:43 · answer #2 · answered by modulo_function 7 · 1 0

1

if sin(θ) = θ then θ = 0
cos(0) = 1

if sin(θ) = x,
cos(θ) = √(1-x²)
works for any value of x, not just small ones.

2006-11-13 00:10:35 · answer #3 · answered by Scott R 6 · 0 1

1/cosC=secC<<<>>>

2006-11-13 00:10:46 · answer #4 · answered by desert 1 · 0 3

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