How would I calculate the final temperature of a mixture made up initially of 70.0 mL liquid water at 28.0 degrees C and 5.0 g ice at 0.0 degrees C?
You don't have to figure out the problem for me, I'm just trying to figure out what formula to use so I can solve it. Thanks!
2006-11-12 15:10:04 · 3 answers · asked by Nick 2 in Science & Mathematics ➔ Chemistry
Conservation of energy.
Calculate the amount of heat stored in the 28ºC water using 0ºC as the starting point. This energy must first melt the ice, for which you'll need to use the heat of fusion of water. The remainder of the energy will warm up the entire amount of water.
2006-11-12 15:14:35 · answer #1 · answered by arbiter007 6 · 0⤊ 0⤋
Q= mass x temperature change x specific heat capacity
2006-11-12 15:18:09 · answer #2 · answered by The Gasconni 2 · 0⤊ 0⤋
calculate least lost through steam Econ= - Ec*g Ec power used to condense 1g of steam water Ec=-2257J/g right here 2257*0.fifty 5= -1241J and upload power lost through cooling water received from 100C to very last temperature tf is E(s)= 4.184*0.fifty 5(tf-one hundred ) = 2.3tf-230 so entire power lost E(s) = -1471 +2.3tf power received through water at 7C is E=4.25*4.184*(tf-7) =17.78tf-124.5 =E(w) You write Ew= - E(s) 1471-2.3tf = 17.78tf-124.5 or 1595.5=20.8 tf tf =1595.5 /20.8= 79C
2016-11-23 18:46:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋