Yes you're correct - just plug in -2 for x to get:
20 - -6 + 1 = 27
2006-11-12 15:08:59
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answer #1
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answered by martina_ie 3
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It's ok. I had to do most of the "high school" math twice. Now I am a Math major :)
think of the f(x) as a graph of all possible values of x, hence the "x"
when you want to evaluate a function at a point, you replace the "x" with whatever the constant is (can be letters or numbers)
your problem f(-2) = 5(-2)^2-3(-2)+1; we are evaluating the function at the point x= -2
hope this helps
2006-11-12 15:13:42
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answer #2
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answered by Anthony A 3
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15
2006-11-12 15:08:39
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answer #3
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answered by Anonymous
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Yes, you replace x with -2:
5*(-2)^2 - 3*(-2) + 1
2006-11-12 15:09:27
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answer #4
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answered by arbiter007 6
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2016-12-14 06:12:52
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answer #5
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answered by ? 4
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f(x)=5x^2 - 3x+1
f(-2)=5*(-2)^2-3*(-2)+1
f(-2)=5*4+6+1=27
2006-11-12 15:22:29
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answer #6
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answered by yupchagee 7
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You are correct, replace x with -2
Instead of giving you the answer, which you seem to want to work out, I'll tell you instead that f(-3) = 55
2006-11-12 15:12:31
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answer #7
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answered by Gary H 6
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5(-2)^2 - 3(-2)+1
5(4) -3(-2)+1
20- -6+1
20+6+1
27
2006-11-12 15:12:03
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answer #8
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answered by R1.8Turbo 1
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f(x)= 5x^2 - 3x+1
f(-2) = 5 * (-2)^2 - 3 * (-2) + 1
f(-2) = 5 * 4 - (-6) + 1
f(-2) = 20 + 6 + 1
f(-2) = 27
2006-11-12 15:09:54
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answer #9
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answered by Iwearpants 2
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f(-2)=(5*-2^2)-(3*-2)+1
f(-2)=(5*4)-(3*-2)+1
f(-2)=20-(-6)+1
f(-2)=20+6+1= +27
2006-11-12 15:21:08
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answer #10
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answered by Todd D 3
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