what to numbers that are added together give you -7 and that are multiplied together give you +60
thank you!
2006-11-12 14:45:55 · 6 answers · asked by chic! 2 in Science & Mathematics ➔ Mathematics
yea, my equation is already x^2-7x+60
2006-11-12 14:53:21 · update #1
thanks everyone! but its hard just because it has to be +60
isnt it no solution? or impossible?
how do you call that?
2006-11-12 14:56:17 · update #2
x+y=-7
xy=60
(x+y)^2=x^2+2xy+y^2
49=x^2+y^2+120
-71=x^2+y^2
x^2>=0 and y^2>=0
so I don't think there is a solution
if their sum is -7 and their product is -60... then 5 and -12 are your numbers
2006-11-12 14:52:31 · answer #1 · answered by buaya123 3 · 0⤊ 0⤋
Let the two numbers be x and y
given that: xy = 60, so y= 60/x
also, x + y = -7
or x + 60/x = -7
x^2 + 60 = -7x
x^2 + 7x + 60=0
factorise this and u get the positive value of x. Divide it by 60 and u get y.
2006-11-12 22:51:18 · answer #2 · answered by K.P. 3 · 0⤊ 0⤋
8
2006-11-12 22:48:05 · answer #3 · answered by rpoker 6 · 0⤊ 0⤋
Not possible. Excluding the use of imaginary numbers, the only thing that comes close is if you are subtracting, in which case it would be -12 and -5.
(-12) - (-5) = (-12) + 5 = -7
-12 * -5= +60
but -12 * 5= -60
If you can use imaginary numbers you can get an answer from the quadratic equation with a result of (-7 (+/-) 13.8207479 i) / 2
the 13.8...i number comes from the sqrt of -191
2006-11-12 22:58:16 · answer #4 · answered by Todd D 3 · 0⤊ 0⤋
5 and -12 but the product of the two will yield -60
2006-11-12 22:52:50 · answer #5 · answered by Phy A 5 · 0⤊ 0⤋
no solution?
2006-11-12 22:56:36 · answer #6 · answered by m0rph0s1s 2 · 0⤊ 0⤋