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2006-11-12 14:25:39 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

AND 4^-3 X 4^-2

2006-11-12 14:26:01 · update #1

sry... and
5^3
-----
5^4

(5^3 over 5^4)

2006-11-12 14:26:42 · update #2

8 answers

Anything to a negative power is the same as 1 over that number to the positive power.

So, 5^-2 = 1 / 5^2 = 1/25

~ ~ ~ ~

When you are multiplying two exponents, if the base is the same you can add the exponents --- for example x^R * x^S = x ^(R+S).

So, 4^-3 * 4^-2 = 4^-5 = 1 / 4^5 = 1/1024

~ ~ ~ ~

When you have two exponents in a fraction, if the base is the same you can subtract the exponents --- for example x^R / x^S = x ^(R-S).

So, for 5^3 / 5^4 = 5^(3-4) = 5^-1 = 1 / 5^1 = 1/5

~ ~ ~ ~

Hope that helped!

~ ♥ ~

2006-11-12 14:28:34 · answer #1 · answered by I ♥ AUG 6 · 1 0

With the negative exponent, just flip the number and change the negative exponent to a positive.

5^-2 = (5/1)^-2 = (1/5)² = 1/25

Do the same for the others.

When you divide exponent, they subtract and when you multiply, they add. BUT the base must be the same!

Let assume B=base and x and y = exponent

b^x / b^y = b^(x-y)
b^x * b^y = b^(x+y)
Example 2^5 / 2^3 = 2^(5-3) = 2^2 = 4
Example 2^3 * 2^2 = 2^(3+2) = 2^5 = 32

2006-11-12 14:28:36 · answer #2 · answered by bourqueno77 4 · 0 0

This Site Might Help You.

RE:
HOw would you solve 5^-2 (5 to the negative second power)?

2015-08-18 15:07:05 · answer #3 · answered by ? 1 · 0 0

okay a number to a negative exponent means to put 1 over the number and then solve so you would have

1
---
5^2

or 1\25

the others you could solve a couple of ways,
i would take the exponent from the top and subtract the exponent from the bottom if the root is the same (5^4\5^2), otherwise solve each and the simplify the fraction

2006-11-12 14:30:49 · answer #4 · answered by j h 2 · 0 0

HOw would you solve 5^-2 (5 to the negative second power)?
5^-2=-5*-5= 25


Additional Details

1 minute ago
AND 4^-3 X 4^-2
4^-3=-4*-4*-4=16*-4 = -64
48 seconds ago
sry... and
5^3 5*5*5 = 25*5 = 125
-----
5^4 5*5*5*5 = 25*25 = 625

125
===== 5
625

2006-11-12 14:30:24 · answer #5 · answered by §@mM¥ 2 · 0 1

5^-2 (5 to the negative second power)?

5^-2=(1/5)^2=1/25=.04

Additional Details

4 minutes ago
AND 4^-3 X 4^-2
(1/4)^3*(1/4)^2=(1/4)^5=1/1024

4 minutes ago
sry... and
5^3
-----
5^4
5^-1=.2

(5^3 over 5^4)

5^-1=1/5=.2

2006-11-12 14:32:27 · answer #6 · answered by yupchagee 7 · 1 0

it is 1 over 5^2 so 1 over 25 and solve the rest accordingly

2006-11-12 14:30:34 · answer #7 · answered by Adam B 2 · 0 0

5^-2=1/(5^2)=1/25=0.04

4^-3 x 4^-2=4^-5=1/(4^5)=.000976563

5^3 / 5^4= 1/ 5= 0.2

2006-11-12 14:46:01 · answer #8 · answered by Todd D 3 · 1 0

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yes you do im studying factorization right now: you multiply y by y^2 then times it by -6y then times it by -2 do the same for the 5 then you combine like terms(remember the negatives) . if u want the answer say so

2016-04-01 01:14:11 · answer #9 · answered by Anonymous · 0 0

= 1/ 5^2=1/25=0.04

2006-11-12 19:21:30 · answer #10 · answered by rami_dad 1 · 0 0

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