i cannot get this right:
28x^3+12ix^2+14x+6i
__________________
7x+3i
2006-11-12 14:20:43 · 3 answers · asked by love_never_wanted_me 1 in Science & Mathematics ➔ Mathematics
I got 4x² + 2. It was actually pretty straightforward once you lay it out like a long division problem.
Take 4x² and multiply it by 7x+3i (since the first term will give us 26x³).
4x² * (7x+3i) = 28x³ + 12ix², leaving us with a remainder of 14x + 6i.
Now take (7x+3i) times 2 to get 14x + 6i.
Therefore your answer is 4x² + 2.
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2006-11-12 14:22:35 · answer #1 · answered by I ♥ AUG 6 · 0⤊ 0⤋
[28x^3 +12ix^2 +14x + 6i]/(7x +3i)
= [(28x^3 +14x) +i(12x^2 + 6)]/(7x + 3i)
The division of two complex expressions (p + iq)/(r + is) is given by:
(pr+qs)/(r^2+s^2) + i (qr-ps)/(r^2+s^2) [EQ I]
So p= 28x^3+14x
q= 12x^2+6
r=7
s= 3
So plug the above expressions into EQ I to get answer.
2006-11-12 15:12:16 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
the answer is 4x^2 +2
2006-11-12 14:31:00 · answer #3 · answered by Anonymous · 0⤊ 0⤋