2006-11-12 14:09:36 · 5 answers · asked by joshnkim63 1 in Science & Mathematics ➔ Chemistry
C12H22O11+12O2-------12CO2+11H2O+E
2006-11-12 14:19:55 · answer #1 · answered by biso 1 · 0⤊ 0⤋
Rather than answering your question directly, given it's probably homework and being it seemed pretty simple 34 years ago when I took 1st quarter chemistry, I'll give you a way to do it.
First try using the carbon subscript on sucrose for the CO2 prefix and the similar hydrogen subscipt (divided by 2) for the water. Then see what else needs to change to balance. Keep playing with it. After a number of these equations, you'll get the feel for how it's done. A more general method uses algebra, but it's not something I have time to explain here.
2006-11-12 14:22:14 · answer #2 · answered by Radagast97 6 · 0⤊ 0⤋
C12h22o11 O2
2017-02-20 16:38:40 · answer #3 · answered by Anonymous · 0⤊ 0⤋
c12h22o11+12o2--12co2+11h2o
2006-11-12 15:24:27 · answer #4 · answered by Eric F 3 · 0⤊ 0⤋
2C12H22O11+35O2(g)--
24CO2(g)+44H20
2006-11-12 14:16:32 · answer #5 · answered by Anonymous · 0⤊ 1⤋