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Element X forms both a dichloride, XCl2 and a tetrachloride, XCl4. treatment of 10.00 g of XCl2 with excess chlorine forms 12.55g XCl4. Calculate the atomic weight(amu) of X and identify X.

2006-11-12 14:04:01 · 2 answers · asked by azncrazygurl520 1 in Science & Mathematics Chemistry

2 answers

Molecular wt of XCl2 is 274.72, since the molecular wt. of Cl2 is 70.9 then the Atomic wt. of x is approx. 204. This is the element Thallium. How did I get 274.72? 10 grams of CCL2 was used yielding 12.55 grams of CCL4. They were in mole to mole proportion.12,55 minus 10 = 2.55 gram Cl2 used to form the CCL4. molecule. 2.55/ 70 = .0364 moles Cl2 used and since they were in 1:1 mole proportion there was .0364 mole of CCL2 which weighed 10 grams.10 gr./MW = No. of moles. MW = 274.72

2006-11-12 15:01:23 · answer #1 · answered by Mad Mac 7 · 0 0

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2016-10-21 23:54:34 · answer #2 · answered by Anonymous · 0 0

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