List the factors...PLEASE!
2006-11-12 13:54:14 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
35 = 5*7
210 = 2*3*5*7
To factor something, start dividing by the smallest prime, if possible, then keep on dividing by larger and larger primes till you run out (i.e., till your remainder is itself prime).
Primes are 2, 3, 5, 7, 11, 13, 17, etc.
So, 35 is not divisible by 2 or 3, but it is divisible by 5, with a remainder of 7, so the factorization stops there. 35 = 5*7
Now, 210 is divisible by 2, with remainder 105
105 is divisible by 3, with remainder 35
35 = 5*7 (from previous problem)
So ... 210 = 2*3*5*7
Hope that helped!
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2006-11-12 13:56:08 · answer #1 · answered by I ♥ AUG 6 · 1⤊ 0⤋
35=7 x 5 (since both 7 and 5 are prime numbers we have found all the factors).
For 210 proceed one step at a time:
210=2 x 105 = 2 x (3 x 35) = 2 x (3 x (7 x 5))=2 x 3 x 7 x 5
2006-11-12 13:58:15 · answer #2 · answered by First L 2 · 1⤊ 0⤋
35*1
5*7*1
210*1
105*2
21*5*2
7*3*5*2
When you get all the numbers to prime form then you have all the factors. Good luck.
2006-11-12 13:59:29 · answer #3 · answered by ldbroyles 2 · 0⤊ 0⤋
35=5*7
210=2*3*5*7
The factors are 2, 3, 5, 7, and 7
2006-11-12 13:56:57 · answer #4 · answered by Anonymous · 0⤊ 0⤋
35: 5 and 7
210: 2,3, 5, and 7
2006-11-12 13:56:45 · answer #5 · answered by George D 4 · 1⤊ 0⤋
35 = 1,5,7,35
210 = 1,2,3,5,6,7,10,14,15,21,35,70,105
2006-11-12 13:59:18 · answer #6 · answered by bourqueno77 4 · 0⤊ 0⤋