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During the standardization of the NaOH solution,a number of changes were made in the procedure, most of them by mistake. explain what effect, if any, each of the changes would have on the calculated molarity of the NaOH

2006-11-12 13:36:52 · 3 answers · asked by bebop_0632 1 in Science & Mathematics Chemistry

3 answers

If you rinse the buret with distilled water, when you add the NaOH to it, there may still be water left in the buret, thus, diluting the concentration of the NaOH solution. This would give you a lower molarity of NaOH than if you rinsed the buret with NaOH solution because mixing NaOH with NaOH (if they are both identical in concentration) would not change the concentration.

2006-11-12 13:40:08 · answer #1 · answered by Anonymous · 0 0

That was a little confusing, but I think you're asking, if you're doing a titration with NaOH solution and you rinse the buret with DI H2O, how that would affect your result. The answer is, when you rinse the buret, some of the liquid you rinsed it with remains in there. If you rinse it with DI H2O, the water left in the buret contains no NaOH and therefore the molarity of your NaOH solution is lightly lower than recorded. You would measure the acid to be slightly stronger than it actually is. By rinsing the buret with the solution you intend to titrate with, you ensure that any liquid remaining in the buret won't affect the overall molarity.

2006-11-12 13:42:09 · answer #2 · answered by Amy F 5 · 0 0

Scriptam has it. Rinse the burette a minimum of as quickly as with the titrant answer. If there is any residue in the burette it is going to oftentimes decrease the Molarity of your titrant (if it reacts with it) and could certainly gain this no rely if that's water (think of roughly it, you're increasing the ratio of water to NaOH so the molarity is lwered as there is far less NaOH consistent with unit quantity of water).

2016-10-17 05:09:53 · answer #3 · answered by reus 4 · 0 0

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