a over 5 equals a-3 over 2. How do i solve this algebra equation?

Answer 1

combine the like terms, which are the a's and the numbers

Answer 2

first make it into an equation. this would make it (a/5)= (a-3)/2.
then you solve the equation.
1. multiply both sides by ten. this will give you 2a= 5(a-3)
2. Now use the substitution methode multiplying 5 with a-3. This will make the equation 2a= 5a-15.
3. now subtract 5a from 2a. This makes it -3a=-15
4. Divede the whole equation by -3.
5. the answer is a=5.

Answer 3

Bring all the a's to one side & the values to the other, so that you have one equation in one unknown.
For ease, first multiply both sides by ten. Then you have
2a = 5a − 15
Subtract 5a from both sides.
−3a = −15
Divide both sides by −3.
a = 5.
See if you can figure out the rest on your own.

Answer 4

a/5=(a-3)/2
Multiplying both terms by 10,the GCM of 2 and 5,e gt
2a=5(a-3)
=>2a=5a-15
=>2a-5a=-15
=>-3a=-15
Therefore a=-15/-3=5

Answer 5

Cross multiply so that you get rid of the fractions...

2a = 5 (a - 3)

Distribute the 5
Isolate the variable
viola!

Answer 6

(a/5) = (a-3)/2

so you wanna multiply both sides by 10, to get rid of the fraction...

2a = 5(a-3)

and then you do the distribution thing.

2a = 5a - 15

then group your 'likes' together...remember to flip your sign when you move it to the other side of the equals sign...

3a = 15

divide both sides by 3..

a = 5

Answer 7

a/5=(a-3)/2

First, get rid of the fractions by multiplying both sides by 5 and 2:

2a/5=a-3
2a=5a-15

Then, combine like terms by subtracting 5a from each side:

-3a=-15

Finally, isolate the variable by dividing both sides by -3:

a=5

Answer 8

the answer is
a/5=a-3/2
a/5X-3/2=15a/2
you cancel both A's
giving you 15/2= 7.5