The same object is dropped in a vacuum and then in air. Which of the parameters (velocity, distance, accelerat

Question

The same object is dropped in a vacuum and then in air. Which of the parameters (velocity, distance, acceleration) vary and which remains constant during succeeding seconds of time.

Answer 1

Assuming gravity is the same and the starting point is the same, distance will not change. Nor should acceleration, but the friction caused by atmosphere will cause the object to fall more slowly.

Answer 2

If you measured all 3 parameters, each second, during both falls you would find all 3 parameters to be less during the fall through air.

Acceleration will be less because there will be drag from the air resistance.
Acceleration is a = Fnet/m.
In vacuum, Fnet = W = m*g, so
a1 = W/m = m*g/m = g
but in air, Fnet = W - drag, so
a2 = (W - drag)/m
This is less acceleration than g.

If acceleration is less in air, velocity each second will be less, and distance will be less each second.

Answer 3

Velocity will vary in vacumn as the due to gravity (if gravity is acted upon)
Velocity will vary in a short time until terminal velocity is reached hence, velocity will constant for the object in the air.

Distance will be vary in succedding seconds of time as the velocity varied in the above scenario

Accerelation is constant at 9.81 (if with respect to earth) in vacumn
Acceleration will gradually decrease to 0 once the terminal velocity is reached in air.