3x^2 - 8x - 5?

Question

Factor Completely

Answer 1

I think you mean
3x² - 8x + 5
(3x-5)(x-1)

If you do mean
3x² - 8x - 5
3x² - 8x - 5 + 10
3x² - 8x + 5
(3x-5)(x-1) - 10

Answer 2

3x^2-8x-5 orginal problem



3x^2 -5x-3x-5 broke the problem up by
having the numbers multiply
up to 15 (5 x 3) and add up to -8


(3x^2 - 5x)(-3x-5) group the factors


x(3x-5) + 1(3x -5 ) pull apart the common factors
to get the same binomials inside
the parentheses

(x +1)(3x-5) gather the factors in one binomial and
the common parentheses in another


hoped i helped

Answer 3

3x^2-8x-5, use the general quadratic formula when it's difficult to get factors of an equation.
ax^2+bx+c
[-b+/- square root((-b)^2-4(a)(c)]/2a
a=3;b= -8;c= -5
-8+/- sqrt[(-8)^2-4(3x-5)]/2(3)
[-8+/- sqrt(64+60)]/6
[-8+sqrt( 124)]/6

(-8+11.135)/6=0.522
Or [-8-sqrt(124)]/6
(-8-11.135)/6= -3.189
no rounding to the nearest digit just the first 3 digits after decimal point.

Answer 4

solve the equation 3x^2 - 8x - 5 = 0 to find out the proof x1,x2
then we have : 3x^2 - 8x - 5 = (x-x1)(x-x2)

Answer 5

Using Quadratic Formula, with a=3, b=-8, c=-5
x=3.1893 or x=-0.5226
You also might want to find out about what is quadratic formula. So, try visiting this websites for the quadratic formula which is found in the algebra section,
www.sosmath.com
www. mathworld.wolfram.com
I hope this helps you.

Answer 6

let's see: there are 4 possible candidates. not sure if any work.

(3x-5)(x+1)
(3x-1)(x+5)
(3x+5)(x-1)
(3x+1)(x-5)

any of these work?

Answer 7

It doesn't factor.