Help with these math probs would be greatly appreciated..?

Question

Find the distance between each pair of points:

1) (-2, -2) and (-4, -4)

2) (-2, 3) and (-7, -1)

3) (6,4) and (-3, 5)

Answer 1

Use the distance formula:

D = √ [ (y2-y1) ² + (x2-x1) ² ]

1) D = √ [ (-2+4) ² + (-2+4) ² ] = √(4+4) = √8 = 2√2

2) D = √ [ (3+1) ² + (-2+7) ² ] = √(16+25) = √41

3) D = √ [ (4-5) ² + (6+3) ² ] = √(1+81) = √82

NRT

Answer 2

We'll use a²+b²=c²

The formula we'll also use is (x2 - x1) = a and (y2 - y1) = b

So:

1) (-2, -2) and (-4, -4)
a = -4 - (-2)
a = -2
b = -4 - (-2)
b = -2
-2² + -2² = c²
4 + 4 = c²
8 = c²
2√2 = c

2) (-2, 3) and (-7, -1)
a = -7 - (-2)
a = -5
b = -1 - 3
b = -4
-5² + -4² = c²
25 + 16 = c²
41 = c²
√41 = c

3) (6,4) and (-3, 5)
a = -3 - 6
a = -9
b = 5 - 4
b = 1
-9² + 1² = c²
81 + 1 = c²
82 = c²
√82 = c

Answer 3

1. 8*1/2

2. 10

3. 7
Note: In "1" the star means to put the following exponent at *. The 1/2 means the square root of or 1/2 power. Graph these to solve them Remember the pythagorean formula: a*2 + b*2 = c*2

Answer 4

the segment from pt (-2,-2) and (-4,-4) can be thought of as a hypotenuse in a right triangle with both sides at the right angle being length = 2. so...2sqrd + 2sqrd = hypotenuse sqrd...

can you finish it? (plotting the points on a graph would help you see it) and this should help you with the next two