Write down all the possible pairs which multiply to 70
and pick out that pair which sums to 17.
Or, try to solve the system
x + y = 17
xy = 70.
So y = x/70,
x + 70/x = 17.
Now multiply each term by x and solve the
resulting quadratic.
Good luck!
2006-11-12 11:34:24
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answer #1
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answered by steiner1745 7
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First find the prime factorization of 70
2*5*7 and 1 and 70
Now, we know that 2*5 + 7 = 17, and so 10 and 7 are your two factors of 70 that have a sum of 17
2006-11-12 19:32:42
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answer #2
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answered by just browsin 6
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Factors of 70:
1,70
2,35
5,14
7,10
So answer: 7+10=17
2006-11-12 19:32:36
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answer #3
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answered by howdowncat313 1
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factors are numbers which you multiply by each other
sum means numbers you add together
so you need to find two numbers which when multiplied by each other = 70 and when added together = 17
Why don't you try witing down a few ways of getting 17 by adding two numbers together and then test these possible answers out by seeing which combination gives you a total of 70 when multiplied
2006-11-12 19:36:52
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answer #4
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answered by jane 62 1
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70 / 7 = 10
7 is a factor
70/10 = 7
10 is factor
7 + 10 = 17. Meet condition. 7,10 OK.
2006-11-12 19:30:51
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answer #5
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answered by Dr. J. 6
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xy=70
x+y=17
x=17-y
(17-y)y=70
17y-y^2=70
0=y^2-17y+70
(y-10)(y-7)=0
numbers are 7 & 10
2006-11-12 20:50:34
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answer #6
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answered by yupchagee 7
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Try this:
10*7=70
10+7=17
I hope that helped!
2006-11-12 19:31:44
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answer #7
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answered by Anonymous
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7 and 10
yay
2006-11-12 19:44:12
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answer #8
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answered by Anonymous
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