physics problem with elevators?

Question

A person is standing on a spring bathroom
scale on the °oor of an elevator which is
moving up and slowing down at the rate of
1:59 m=s2.
The acceleration of gravity is 9:8 m=s2 :
If the person's mass is 83:1 kg, what does
the scale read? Answer in units of n.

Answer 1

1
1
v 83.1kg

T Elevator floor
^
1 Upward force, P=reading

I hope the diagram doesn't get distorted when sent to you.

Since the elevator is slowing down then the net force must be opposite to direction of the elevator, i.e. downward. Therefore,

F=83.1g-P

But F=ma

Substitute known values:

83.1g-P=83.1*1.59
814.4-P=132.1
P=814.4-132.1
P=682N upward. This is the reading on the scale or
69.6kg

Answer 2

a) consistent velocity implies no stress. hence, it would study sixty 8 kg. b) comparable. sixty 8 kg c) ok, so now think of being in an elevator that hurries up upward. you will possibly experience heavier, good? An accelerating elevator is corresponding to an inertial physique with downward stress of F = ma = (sixty 8 kg)(0.33g). This stress is the greater "weight" that the dimensions reads, so (sixty 8 kg)(0.33g) = Mg, so M = (sixty 8 kg * 0.33) = 22.4 kg. that's the greater "mass", so the dimensions reads a finished of: 22.4 kg + sixty 8 kg = ninety.4 kg d) comparable, in the different direction: sixty 8 kg - 22.4 kg = 40 5.6 kg

Answer 3

Normally W = m*g
In this case, W = m*(g-1:59 m=s2)