A wire is first bent into the shape of a square with side 7 cm. The wire is then bent into the shape of a rectangle, with a length of 9 cm. What is the width of the rectangle?
2006-11-12 11:05:16 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5 cm.
7cm x 4 sides = 28
We know all 4 sides of the square are the same.
We also know that a rectangle has 2 sides the same and the other two sides the same.
9cm x 2 sides = 18
28-18=10
10 /2=5
2006-11-12 11:06:51 · answer #1 · answered by divinephi 3 · 0⤊ 2⤋
the length of the wire is : 7*4 = 28cm
we have P = 2 W + 2 L => W = P/2 - L = 5 cm
2006-11-12 19:08:26 · answer #2 · answered by James Chan 4 · 0⤊ 2⤋
5
2006-11-12 19:13:30 · answer #3 · answered by iluvthecreek 2 · 0⤊ 2⤋
5 cm.
7cm x 4 sides = 28
all 4 sides of the square are the same.
a rectangle has 2 sides the same and the other two sides the same.
9cm x 2 sides = 18
28-18=10
10 /2=5
2006-11-12 19:13:08 · answer #4 · answered by STAN 3 · 0⤊ 2⤋
the wire you have is 28 cm long. If the length is 9cm you are using 18 cm of the wire so 10 cm is left making the width 5cm
2006-11-12 19:07:56 · answer #5 · answered by MollyMAM 6 · 0⤊ 2⤋
7 x 4 = 28
9 + 9 = 18
28 - 18 = 10
10/2 = 5
5 is the answer
2006-11-12 19:09:11 · answer #6 · answered by marklemoore 6 · 0⤊ 2⤋
5 cm
The perimeter of each are equal:
Square = 7 + 7 + 7 + 7 = 28 cm
Rectangle = 9 + 9 + 2x = 28 cm,
so 2x = 10 cm,
x = 5 cm
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2006-11-12 19:07:29 · answer #7 · answered by I ♥ AUG 6 · 0⤊ 2⤋
5 cm
2006-11-12 19:07:26 · answer #8 · answered by Moonlit Jazz 3 · 0⤊ 2⤋
5cm
2006-11-12 19:09:03 · answer #9 · answered by Charles 2 · 0⤊ 2⤋
is this a homework problem?
2006-11-12 19:07:04 · answer #10 · answered by ツ Andrea*♥ 4 · 0⤊ 2⤋