A wire is first bent into the shape of an equilateral triangle with side 16 in The wire is then bent into the shape of a square. What is the length of a side of the square?
Does anybody knows this answer?
Only Serious answers please!
2006-11-12 10:42:36 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The perimeter of the triangle is 48 so you divide that by 4 and the length of each side is 12 inches
2006-11-12 10:45:29 · answer #1 · answered by MollyMAM 6 · 0⤊ 0⤋
Yep, 12 inches is the answer. First you have to find the perimeter of the equilateral triangle; the formula for that is: p = 3s.
The perimeter of this triangle is 3 * 16 which equals 48.
The next step is to make it a square. You know that all the sides of the square are equal and there are four sides. In fact, the formula for finding the perimeter of a square is: p = 4s.
You know the perimeter: 48, so plug that in for p.
48 = 4s
Now solve you s:
12 = s
The length of the side of the square is 12 inches!
2006-11-12 18:51:34 · answer #2 · answered by Jose N 2 · 1⤊ 0⤋
Since the triangle is 16"/side, the length of the wire must be 3 times that , or 48. Rebending it into a square of 4 equal sides yields sides of 48/4 = 12".
2006-11-12 18:46:45 · answer #3 · answered by Gary H 6 · 0⤊ 0⤋
12 16*3 answer / 4
2006-11-12 18:45:10 · answer #4 · answered by Gary G 1 · 0⤊ 0⤋
16*3=48
48/4=12
the answr is 12 inches
2006-11-12 18:45:41 · answer #5 · answered by SteveA8 6 · 0⤊ 0⤋
12 inches
2006-11-12 18:45:40 · answer #6 · answered by Treat 2 · 0⤊ 0⤋
12in
2006-11-12 18:44:24 · answer #7 · answered by lazy 1 · 0⤊ 0⤋
sorry
2006-11-12 18:47:18 · answer #8 · answered by Anonymous · 0⤊ 0⤋