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Simplify by combining like terms:
[(sqrt20)/5] + [2/(sqrt5)]

2006-11-12 09:13:07 · 6 answers · asked by Anonymous in Education & Reference Homework Help

6 answers

The answer is: 4.47, and that's all there is to it!

Ok Vanessa, all you have to do is pull up your calculator (Start>Accessories).
I am not suggesting you don't work it out in your head first: it's just basic. Check the answer on the calc, or, if you get stuck....go back.... to POWERS OF HIGH HOLY ROOTISM SQUARE YOU KNOW, 1x1+(2x2)+2+(10-5)/1= Simple:
1+4+2+5/1=12

2006-11-12 09:24:05 · answer #1 · answered by GiGi 4 · 0 0

first of all: sqrt20 = sqrt(4*5) right? Sqrt4 = 2 so you can take that out from under the square root sign....you get 2(sqrt5).

now: [2(sqrt5)/5] + [2/(sqrt5)]

To get rid of a sqrt as a demoninator, you need to multiply the denominator by itself. but you can't just multiply sqrt5 to itself for no reason...you have to multiply that to the numerator as well.

so you get:
[2(sqrt5)/5] + [[2/(sqrt5)] X [(sqrt5/sqrt5)]]

now you simplify.... sqrt5 X sqrt5 = 5
2 X sqrt5= 2(sqrt5)
So you get:

[2(sqrt5)/5] + [2(sqrt5)/5]

you can further simplify because there are 2 common denominators...

[2(sqrt5) + 2(sqrt5)] / 5

2(sqrt5)+ 2(sqrt5) = 4(sqrt5) (you can think of sqrt5 as a variable. like apple. 2apples + 2 apples = 4 appls)

Final answer:
4(sqrt5)/5


I really hope that helps. typing on the computer is really inefficient for math problems but just write what I typed out on paper and things will become clearer, ok? good l uck!

2006-11-12 09:28:46 · answer #2 · answered by Molley K 1 · 0 1

Ok, I used to love math, but I haven't had it in a LONG time and I forgot a lot of stuff, but I'm gonna try this one. :) Forgive me if this is wrong!

Ok first I multiplied each side by (sqrt2) so I could get common denomonators. Then it was

(sqrt2)sqrt20/(sqrt2)5 + (sqrt2)2/(sqrt2)sqrt5

If you multiply the 2 and the 20 you get 40 so it's

sqrt(sqrt40)/(sqrt2)5

Then multiply the 2 and the 5 on the bottum to get sqrt10
So it's sqrt(sqrt40)/sqrt10

Then multiply the 2 and the 2 on the top of the other one to get sqrt4(sqrt)
Then multiply the 2 and the 5 on the bottum to get sqrt10 on that denomonator. So now it's:

sqrt(sqrt)40/sqrt10 + (sqrt)sqrt4/sqrt10

Then simplify:

you can cancel out the sqrt on the top and bottum of the first one. so you're left with sqrt40/10 then 10 goes into 40, 4 times so you get sqrt4

Then on the other one youc an cancel out the sqrt on the top and one on the bottum. so you have 4/sqrt10 then divide the 4/10 by 2 and you get 2/5.

So you're left with sqrt4+2/sqrt5

hope it's right! :) And I hope you understood it! good luck! :)

2006-11-12 09:28:42 · answer #3 · answered by Sam 1 · 1 0

multiply 2/√5 by √5/√5 to get a common denominator:

√20 / 5 + 2/√5 =

√20 / 5 + (2/√5)(√5/√5) =

√20 / 5 + 2√5 / 5 =

√(4*5) / 5 +2√5 / 5 =

2√5 / 5 + 2√5 / 5 =

4√5 / 5

NRT

2006-11-12 09:19:30 · answer #4 · answered by New Rule Tomorrow 2 · 1 0

4qrst + 2/5qrst = 4.4 or 4 2/5 qrst

original: [(sqrt20)/5] + [2/(sqrt5)]

20qrst /5 = 4qrst

2/5 qrst = 2/5 qrst or 0.4 qrst

add.

4qrst + 2/5 qrst= 4.4 qrst

2006-11-12 09:18:23 · answer #5 · answered by soccerkish21 1 · 0 0

[2/sqrt5] x sqrt5/sqrt5 = 2sqrt5/5

[sqrt20/5] + [2sqrt5/5] then combine = (sqrt20 + 2sqrt5)/ 5

2006-11-12 09:19:09 · answer #6 · answered by Kelly 2 · 0 0

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